[2021-New] Cisco 100-105 Dumps With Update Exam Questions (91-100)

100-105 Dumps

100-105 Exam Questions - Online Test

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Q1. - (Topic 3)

A router has learned three possible routes that could be used to reach a destination network. One route is from EIGRP and has a composite metric of 20514560. Another route is from OSPF with a metric of 782. The last is from RIPv2 and has a metric of 4. Which route or routes will the router install in the routing table?

A. the OSPF route

B. the EIGRP route

C. the RIPv2 route

D. all three routes

E. the OSPF and RIPv2 routes

Answer: B

Explanation:

When one route is advertised by more than one routing protocol, the router will choose to use the routing protocol which has lowest Administrative Distance. The Administrative Distances of popular routing protocols are listed below:

Q2. - (Topic 3)

Which parameter or parameters are used to calculate OSPF cost in Cisco routers?

A. Bandwidth

B. Bandwidth and Delay

C. Bandwidth, Delay, and MTU

D. Bandwidth, MTU, Reliability, Delay, and Load

Answer: A

Explanation:

The well-known formula to calculate OSPF cost is Cost = 108/ Bandwidth

Q3. - (Topic 5)

How can you ensure that only the MAC address of a server is allowed by switch port Fa0/1?

A. Configure port Fa0/1 to accept connections only from the static IP address of the server.

B. Configure the server MAC address as a static entry of port security.

C. Use a proprietary connector type on Fa0/1 that is incomputable with other host connectors.

D. Bind the IP address of the server to its MAC address on the switch to prevent other hosts from spoofing the server IP address.

Answer: B

Explanation:

When the MAC address is configured as static entry, no other address is allowed.

Q4. - (Topic 1)

Which two characteristics describe the access layer of the hierarchical network design model? (Choose two.)

A. layer 3 support

B. port security

C. redundant components

D. VLANs

E. PoE

Answer: B,D

Explanation:

Access layer The main purpose of the access layer is to provide direct connection to devices on the network and controlling which devices are allowed to communicate over it. The access layer interfaces with end devices, such as PCs, printers, and IP phones, to provide access to the rest of the network. The access layer can include routers, switches, bridges, hubs, and wireless access points (AP).

Switch features in the Access layer:

......

Port security

VLANs

Fast Ethernet/Gigabit Ethernet

Power over Ethernet (PoE)

Link aggregation

Quality of Service (QoS)

References: http://www.ciscopath.com/content/61/ http://www.mcmcse.com/cisco/guides/hierarchical_model.shtml

Topic 2, LAN Switching Technologies

Q5. - (Topic 3)

Refer to the exhibit.

A network associate has configured OSPF with the command:

City(config-router)# network 192.168.12.64 0.0.0.63 area 0

After completing the configuration, the associate discovers that not all the interfaces are participating in OSPF. Which three of the interfaces shown in the exhibit will participate in OSPF according to this configuration statement? (Choose three.)

A. FastEthernet0 /0

B. FastEthernet0 /1

C. Serial0/0

D. Serial0/1.102

E. Serial0/1.103

F. Serial0/1.104

Answer: B,C,D

Explanation:

The “network 192.168.12.64 0.0.0.63 equals to network 192.168.12.64/26. This network has:

Increment: 64 (/26= 1111 1111.1111 1111.1111 1111.1100 0000)

Network address: 192.168.12.64

Broadcast address: 192.168.12.127

Therefore all interface in the range of this network will join OSPF.

Q6. - (Topic 3)

Which two statements describe the IP address 10.16.3.65/23? (Choose two.)

A. The subnet address is 10.16.3.0 255.255.254.0.

B. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.

C. The last valid host address in the subnet is 10.16.2.254 255.255.254.0

D. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.

E. The network is not subnetted.

Answer: B,D

Explanation:

The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254

Q7. - (Topic 1)

Which network device functions only at Layer 1 of the OSI model? A. Option A

B. Option B

C. Option C

D. Option D

E. Option E

Answer: B

Explanation:

Most hubs are amplifying the electrical signal; therefore, they are really repeaters with several ports. Hubs and repeaters are Layer 1 (physical layer) devices.

Q8. - (Topic 3)

Refer to the exhibit.

The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?

A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0

B. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0

C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0

D. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0

Answer: A

Explanation:

Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A

through FastEthernet interface. The interface cost is calculated with the formula 108 /

Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the

cost is 12 (learned from Router_A) + 1 = 13 for both subnets ->

The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps =

64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link ->

Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.

In fact, we can quickly eliminate answers B, C and D because they contain at least one

subnet learned from Serial1/0 -> they are surely incorrect.

Q9. - (Topic 7)

Refer to the exhibit.

Which statement describes the effect of this configuration?

A. The VLAN 10 VTP configuration is displayed.

B. VLAN 10 spanning-tree output is displayed.

C. The VLAN 10 configuration is saved when the router exits VLAN configuration mode.

D. VLAN 10 is added to the VLAN database.

Answer: D

Q10. - (Topic 3)

Refer to the output of the corporate router routing table shown in the graphic.

The corporate router receives an IP packet with a source IP address of 192.168.214.20 and a destination address of 192.168.22.3.

What will the router do with this packet?

A. It will encapsulate the packet as Frame Relay and forward it out interface Serial 0/0.117.

B. It will discard the packet and send an ICMP Destination Unreachable message out interface FastEthernet 0/0.

C. It will forward the packet out interface Serial 0/1 and send an ICMP Echo Reply message out interface serial 0/0.102.

D. It will change the IP packet to an ARP frame and forward it out FastEthernet 0/0.

Answer: B

Explanation:

Since the destination network is not in the routing table, and no default gateway has been configured, the router will discard the packet and send an ICMP Destination Unreachable message out interface FastEthernet 0/0. It knows to send it out Fa 0/0 because the routing table for the source IP address of 192.168.214.20 shows it was learned from the Fa 0/0 interface.